chris/CountFolderFiles
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Changed the rename to check for ' [' instead of '['. That way if there is a [ symbol in the directory already, it won't skip it unless it is using the same 2 space prefix. Also it looks cleaner to have it spaced out. May change it to a different prefix later.

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admin 2024-05-19 15:46:47 -04:00
parent bd9f268f52
commit d64ec57b69
1 changed files with 4 additions and 4 deletions
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8
CountFolderFiles.py
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@ -7,7 +7,7 @@ def append_to_folder_name(folder_path, suffix):
base_folder_name = os.path.basename(folder_path) base_folder_name = os.path.basename(folder_path)
# Append the suffix to the folder name # Append the suffix to the folder name
new_folder_name = f"{base_folder_name}[{suffix}]" new_folder_name = f"{base_folder_name} [{suffix}]"
# Rename the folder # Rename the folder
os.rename(folder_path, os.path.join(os.path.dirname(folder_path), new_folder_name)) os.rename(folder_path, os.path.join(os.path.dirname(folder_path), new_folder_name))
@ -62,7 +62,7 @@ def clean_directory_name(directory_name):
last_backslash_index = directory_name.rfind('\\') last_backslash_index = directory_name.rfind('\\')
# Find the first occurrence of '[' after the last backslash # Find the first occurrence of '[' after the last backslash
last_open_bracket_index = directory_name.find('[', last_backslash_index) last_open_bracket_index = directory_name.find(' [', last_backslash_index)
# If '[' exists after the last backslash, remove everything after it # If '[' exists after the last backslash, remove everything after it
if last_open_bracket_index != -1: if last_open_bracket_index != -1:
@ -71,7 +71,7 @@ def clean_directory_name(directory_name):
# If '[' doesn't exist, keep the original string # If '[' doesn't exist, keep the original string
return directory_name return directory_name
else: else:
return directory_name.rsplit("[", 1)[0] return directory_name.rsplit(" [", 1)[0]
def main(): def main():
if len(sys.argv) < 2: if len(sys.argv) < 2:
@ -88,7 +88,7 @@ def main():
if check_directory_exists(directory_name): if check_directory_exists(directory_name):
print(f"Directory '{directory_name}' exists.") print(f"Directory '{directory_name}' exists.")
#If folder was counted already, remove the old count. Ex: dirname[1] -> dirname #If folder was counted already, remove the old count. Ex: dirname_[1] -> dirname
os.rename(directory_name, os.path.join(os.path.dirname(directory_name), directory_name_cleaned)) os.rename(directory_name, os.path.join(os.path.dirname(directory_name), directory_name_cleaned))
directory_name = directory_name_cleaned directory_name = directory_name_cleaned