From d64ec57b69f5c1825cb7fb61158455f30203f28e Mon Sep 17 00:00:00 2001
From: admin <admin>
Date: Sun, 19 May 2024 15:46:47 -0400
Subject: [PATCH] Changed the rename to check for '  [' instead of '['. That
 way if there is a [ symbol in the directory already, it won't skip it unless
 it is using the same 2 space prefix. Also it looks cleaner to have it spaced
 out. May change it to a different prefix later.

---
 CountFolderFiles.py | 8 ++++----
 1 file changed, 4 insertions(+), 4 deletions(-)

diff --git a/CountFolderFiles.py b/CountFolderFiles.py
index 68b6005..c14b3e5 100644
--- a/CountFolderFiles.py
+++ b/CountFolderFiles.py
@@ -7,7 +7,7 @@ def append_to_folder_name(folder_path, suffix):
         base_folder_name = os.path.basename(folder_path)
         
         # Append the suffix to the folder name
-        new_folder_name = f"{base_folder_name}[{suffix}]"
+        new_folder_name = f"{base_folder_name}  [{suffix}]"
         
         # Rename the folder
         os.rename(folder_path, os.path.join(os.path.dirname(folder_path), new_folder_name))
@@ -62,7 +62,7 @@ def clean_directory_name(directory_name):
         last_backslash_index = directory_name.rfind('\\')
     
         # Find the first occurrence of '[' after the last backslash
-        last_open_bracket_index = directory_name.find('[', last_backslash_index)
+        last_open_bracket_index = directory_name.find('  [', last_backslash_index)
     
         # If '[' exists after the last backslash, remove everything after it
         if last_open_bracket_index != -1:
@@ -71,7 +71,7 @@ def clean_directory_name(directory_name):
             # If '[' doesn't exist, keep the original string
             return directory_name
     else:
-        return directory_name.rsplit("[", 1)[0]
+        return directory_name.rsplit("  [", 1)[0]
 
 def main():
     if len(sys.argv) < 2:
@@ -88,7 +88,7 @@ def main():
         if check_directory_exists(directory_name):
             print(f"Directory '{directory_name}' exists.")
 
-            #If folder was counted already, remove the old count. Ex: dirname[1] -> dirname
+            #If folder was counted already, remove the old count. Ex: dirname_[1] -> dirname
             os.rename(directory_name, os.path.join(os.path.dirname(directory_name), directory_name_cleaned))
             directory_name = directory_name_cleaned